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PHYSICS 313
Sessional exam, December 10 2002
Answer 4 out of the 5 problems. All problems have equal value. If all 5 problems are attempted credit will be given for the best 4 answers. A number of potentially useful formulas are given at the end of the paper. Time 2 $\frac{1}{2}$ hours. Allowed aids three sheets of notes (6 pages), calculator.

Problem 1:
An imperfect gas satisfies the van der Waals equation of state. The Helmholtz free energy can be written

\begin{displaymath}F=-Nk_BT(\ln (\frac{V-Nb}{Nv_q})+1)-\frac{a N^2}{V}\end{displaymath}

where $a$ and $b$ are constants and

\begin{displaymath}v_q=(\frac{2\pi\hbar^2}{mk_BT})^{3/2}\end{displaymath}

a: Find the entropy of such a gas with $N$ particle at temperature $T$, volume $V$.
b: What is the heat capacity $C_V$, under the conditions of a: ?
c: The gas is expanded from volume $V$ to 2$V$, keeping the temperature constant. Problem 2:
In a hydrogen fuel cell the chemical reactions are
Some thermodynamic properties per mol of the constituents at 298 K, 1 bar are listed below

Substance $\Delta H$(kJ) $\Delta G$(kJ) $S$(JK$^{-1})$ $C_P$(JK$^{-1})$ $V$(cm$^3$)
$H_2$ 0 0 130.68 28.82  
$H_2O$ -285.83 -237.13 69.91 75.29 18.068
$O_2$ 0 0 205.14 29.38  
a: What is the voltage of the cell?
b: What is the change in the Gibbs free energy for the constituents if the pressure of the oxygen, hydrogen and water each are increased from 1 bar to 10 bar. The temperature is kept constant at 298 K. Neglect any volume change of the liquid water with pressure.
c: How much will the voltage of the cell increase or decrease after the pressure has been increased?
Problem 3:
You have a system in which particles can occupy any one of two energy levels with energy $\epsilon_1$ and $\epsilon_2$ respectively. Assume that there are two particles in the system and that the temperature is given by $\beta=1/k_BT$. Find the probability that any one particle is in state 1 and the other in 2 if
a: The particles are distinguishable.
b: The particles are identical and two particles are forbidden from occupying the same state (fermions).
c: The particles are identical and several particles are allowed to occupy the same state (bosons).
Problem 4:
One mole of a monatomic ideal gas is initially at 300 K and 1 bar. The system then undergoes the following cyclic sequence of processes: a: Draw a PV diagram for the cycle?
b: Will the system work as an engine or a heat pump? Justify your answer!
c: Work out the heat and work for each step of the cycle. Specify if the heat and work is added to the system or taken from it.
Problem 5:
The temperature and of air at ground level is 293 K. The saturation vapor pressure at that temperature is 0.023 bar and the actual partial pressure 50% of that (50% relative humidity). The latent heat of evaporation of water around that temperature is 44 KJ/mol. Assume that the temperature drops at a rate of 1 K per 100 m.
a: Neglect the pressure drop with altitude and estimate at what altitude will the saturation water pressure be exceeded, and a cloud forms.
b: Not only the temperature, but also the pressure will drop with altitude. Estimate how much the vapor pressure has dropped at the altitude you calculated under a:.
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Some formulas:
$G=\mu N=U+PV-TS=\mu N$ Gibbs free energy
$F=U-TS$ Helmholtz free energy
$H=U+PV$ Enthalpy.
Differential forms

\begin{displaymath}dU=TdS-PdV+\mu dN,\;\; dH=TdS+VdP+\mu dN\end{displaymath}


\begin{displaymath}dF=-SdT-PdV+\mu dN,\;\; dG=-SdT+VdP+\mu dN\end{displaymath}

Heat capacity/mol at constant volume of ideal gas

\begin{displaymath}C_V=\frac{fR}{2}\end{displaymath}

$f=$ number of thermodynamic degrees of freedom/molecule, with $f=3$ for monatomic gas, $f=5$ for air.
Clausius Clapeyron equation

\begin{displaymath}\frac{dP}{dT}=\frac{L}{T\Delta V}\end{displaymath}

approximate formula for vapor pressure

\begin{displaymath}P=const.\times \exp(-\frac{L}{RT}\end{displaymath}

Adiabatic process

\begin{displaymath}V_iT_i^{f/2}=V_fT_f^{f/2}\end{displaymath}

Some constants

\begin{displaymath}R=8.315\; {\rm J mole}^{-1}{\rm K}^{-1}\end{displaymath}


\begin{displaymath}1 \;{\rm bar}=10^5 \;{\rm N\;m}^{-2}\end{displaymath}


\begin{displaymath}N_A=6.022\times10^{23}\end{displaymath}


\begin{displaymath}0^o{\rm C}=273.16\;{\rm K}\end{displaymath}

The mass of a water molecule is $18\times 1.673\times 10^{-27}$ kg.
The charge of an electron is $-1.602\times 10^{-19}$ Coulomb.


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Birger Bergersen 2003-01-03